document.write( "Question 405360: The perimeter of a rectangle is 80 feet, and it's length is 5 feet less than twice its width. Find the length and width. \n" ); document.write( "
Algebra.Com's Answer #286314 by algebrahouse.com(1659)\"\" \"About 
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\"The perimeter of a rectangle is 80 feet, and it's length is 5 feet less than twice its width. Find the length and width.\"\r
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\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "2x - 5 = length {length is five feet less than twice its width}\r
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\n" ); document.write( "\n" ); document.write( "2(x) + 2(2x - 5) = 80 {two times length + 2 times width = perimeter}
\n" ); document.write( "2x + 4x - 10 = 80 {used distributive property}
\n" ); document.write( "6x - 10 = 80 {combined like terms}
\n" ); document.write( "6x = 90 {added 10 to both sides}
\n" ); document.write( "x = 15 {divided both sides by 6}
\n" ); document.write( "2x - 5 = 25 {substituted 15 in, for x, into 2x - 5}\r
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\n" ); document.write( "\n" ); document.write( "width = 15 feet
\n" ); document.write( "length = 25 feet
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