document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=405209>Question 405209</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangular Persian carpet has a perimeter of 184 inches. The length of the carpet is 20 inches more than the width. What are the dimensions of the carpet? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286251 by </B><A HREF=/tutors/aboutme.mpl?userid=Jstrasner><B>Jstrasner(112)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Jstrasner><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Jstrasner><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286251\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hey,<BR>\n" );
document.write( "So first the perimeter of a rectangle is 2L (length) + 2W (width)<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "2L + 2W = 184<BR>\n" );
document.write( "Also:<BR>\n" );
document.write( "L = W + 20<BR>\n" );
document.write( "We can substitute W + 2 for L in the first equation:<BR>\n" );
document.write( "2(W + 20) + 2W = 184 => 2W + 40 + 2W = 184 => 4W + 40 = 184<BR>\n" );
document.write( "We subtract 40 from both sides: 4W = 144<BR>\n" );
document.write( "Then we divide both sides by 4: W = 36 <BR>\n" );
document.write( "Then we plug this in to the other equation: L = 36 + 20 = 56<BR>\n" );
document.write( "Therefore:<BR>\n" );
document.write( "Width = 36<BR>\n" );
document.write( "Length = 56<BR>\n" );
document.write( "I hope this helps! </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );