document.write( "Question 404979: I could really use some help with this:\r
\n" ); document.write( "\n" ); document.write( "\"The sum of the numerator and denominator of a fraction is 40. If 3 is added to the numerator, and 2 added to the denominator, the new fraction is equal to 4/5. \r
\n" ); document.write( "\n" ); document.write( "What is the original fraction? \"
\n" ); document.write( "

Algebra.Com's Answer #286172 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The sum of the numerator and denominator of a fraction is 40. If 3 is added to the numerator, and 2 added to the denominator, the new fraction is equal to 4/5.
\n" ); document.write( "What is the original fraction? \"
\n" ); document.write( "-----------------
\n" ); document.write( "Let the original fraction be x/y.
\n" ); document.write( "---
\n" ); document.write( "Equations:
\n" ); document.write( "x + y = 40
\n" ); document.write( "(x+3)/(y+2) = 4/5
\n" ); document.write( "----
\n" ); document.write( "Modify the 2nd equation as follows:
\n" ); document.write( "5(x+3) = 4(y+2)
\n" ); document.write( "5x+15 = 4y+8
\n" ); document.write( "5x-4y = -7
\n" ); document.write( "------
\n" ); document.write( "Now, solve the system:
\n" ); document.write( "x+y = 40
\n" ); document.write( "5x-4y = -7
\n" ); document.write( "---
\n" ); document.write( "Multiply the 1st equation by 5:
\n" ); document.write( "5x + 5y = 5*40
\n" ); document.write( "5x-4y = -7
\n" ); document.write( "-----
\n" ); document.write( "Subtract the bottom eq. from the top and solve for \"y\":
\n" ); document.write( "9y = 207
\n" ); document.write( "y = 23
\n" ); document.write( "---
\n" ); document.write( "Solve for \"x\":
\n" ); document.write( "x + y = 40
\n" ); document.write( "x + 23 = 40
\n" ); document.write( "x = 17
\n" ); document.write( "-------
\n" ); document.write( "Original Fraction: 17/23
\n" ); document.write( "=============================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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