document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404830>Question 404830</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 3% salt solution must be mixed<BR>\n" );
document.write( "with 50 gallons of a 7% solution to obtain 5% solution?\r<BR>\n" );
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document.write( "please help me out? Thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286171 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> how many gallons of a 3% salt solution must be mixed with 50 gallons of a 7% solution to obtain 5% solution? <BR>\n" );
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document.write( "Let x = amt of 3% solution required<BR>\n" );
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document.write( ".03x + .07(50) = .05(x+50)<BR>\n" );
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document.write( ".03x + 3.5 = .05x + 2.5<BR>\n" );
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document.write( "3.5 - 2.5 = .05x - .03x<BR>\n" );
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document.write( "1 = .02x<BR>\n" );
document.write( "x = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=1%2F.02 ALIGN=MIDDLE  ALT=\"1%2F.02\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 50 gal of 3% required, to mix with 50 gal of 7% solution<BR>\n" );
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