document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404903>Question 404903</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the equation is: 3(squared)+ 2(squared) -1(squared)<BR>\n" );
document.write( "                            over<BR>\n" );
document.write( "                 8 divided by 2 times 6 times 1 divided by 6<BR>\n" );
document.write( "im asked to simplify. I have attempted this 7 times now and cannot seem to get the correct ans. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286154 by </B><A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><B>IWork4Dessert(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IWork4Dessert><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286154\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The most important thing to remember with this type of problem is PEMDAS, or order of operations.<BR>\n" );
document.write( "P: parentheses<BR>\n" );
document.write( "E: exponents<BR>\n" );
document.write( "M: multiplication<BR>\n" );
document.write( "D: division<BR>\n" );
document.write( "A: addition<BR>\n" );
document.write( "S: subtraction<BR>\n" );
document.write( "You can remember this acronym through the phrase \"please excuse my dear Aunt Sally\". If you solve a problem in this order, tackling each of these things one at a time, you will end up with the correct answer. <BR>\n" );
document.write( "3^2+2^2-1^2<BR>\n" );
document.write( "Start with the top part of the equation.<BR>\n" );
document.write( "The first thing that you see in PEMDAS is the \"e\", or exponents. Before you add the numbers, square them.<BR>\n" );
document.write( "3^2=3x3=9<BR>\n" );
document.write( "2^2=2x2=4<BR>\n" );
document.write( "-1^2=-1x-1=1 (negatives cancel out)<BR>\n" );
document.write( "Now you add. <BR>\n" );
document.write( "9+4+1=14<BR>\n" );
document.write( "Now that the top part has been simplified, go on to the bottom part. <BR>\n" );
document.write( "8÷2x6x1÷6<BR>\n" );
document.write( "You work the \"m\" and the \"d\", or the multiplication and division, in order from left to right. <BR>\n" );
document.write( "8÷2=4<BR>\n" );
document.write( "4x6=24<BR>\n" );
document.write( "24x1=24<BR>\n" );
document.write( "24÷6=4<BR>\n" );
document.write( "Which means that your top and bottom parts together are 14/4. This can simplify out to 7/2, or 3 1/2.<BR>\n" );
document.write( "Hope this helped! </SPAN>\n" );
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