document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404939>Question 404939</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a standard high school basketball court is 268 ft. The length is 34 ft longer than the width. Find the dimensions of the court.<BR>\n" );
document.write( "show the equation setup </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286148 by </B><A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><B>IWork4Dessert(60)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=IWork4Dessert><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=IWork4Dessert><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let length equal \"w+34\" and width equal \"w\". <BR>\n" );
document.write( "You know that the total perimeter is 268 feet and that you need to add all sides together to get the perimeter. Thus:<BR>\n" );
document.write( "(w+34)+(w+34)+w+w=268 feet<BR>\n" );
document.write( "4w+68=268<BR>\n" );
document.write( "4w=200<BR>\n" );
document.write( "w=50<BR>\n" );
document.write( "Now plug it back in. <BR>\n" );
document.write( "w=50<BR>\n" );
document.write( "w+34=84<BR>\n" );
document.write( "And there's your answer.<BR>\n" );
document.write( "width=50<BR>\n" );
document.write( "length=84<BR>\n" );
document.write( "You can also plug it back in to make sure it's right. <BR>\n" );
document.write( "84+84+50+50=268<BR>\n" );
document.write( "168+100=268<BR>\n" );
document.write( "268=268 &#8730; </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );