document.write( "Question 404841: given that the angle of a triangle are (2x+20), (x+25) and (2x-15), calculate the size of each angle \n" ); document.write( "
Algebra.Com's Answer #286122 by keksjr(7)\"\" \"About 
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Taking the angle of the triangle to be:\r
\n" ); document.write( "\n" ); document.write( "A=2x+20; B=x+25; C=2x-15.\r
\n" ); document.write( "\n" ); document.write( "The sum of angle in a triangle is equal to 180°\r
\n" ); document.write( "\n" ); document.write( "Sum up the angles: A+B+C=180°
\n" ); document.write( " (2x+20)+(x+25)+(2x-15)=180
\n" ); document.write( "Clear the parentheses 2x+20+x+25+2x-15=180
\n" ); document.write( " 5x =180-20-25+15
\n" ); document.write( " 5x =150
\n" ); document.write( "Divide through by 5: x =30\r
\n" ); document.write( "\n" ); document.write( "For Angle A: A=2x+20
\n" ); document.write( " A=2(30)+20
\n" ); document.write( " A=60+20
\n" ); document.write( " A=80°\r
\n" ); document.write( "\n" ); document.write( "For Angle B: B=X+25
\n" ); document.write( " B=30+25
\n" ); document.write( " B=55°\r
\n" ); document.write( "\n" ); document.write( "For Angle C: C=2x-15
\n" ); document.write( " C=2(30)-15
\n" ); document.write( " C=60-15
\n" ); document.write( " C=45°\r
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