document.write( "Question 404520: In how many ways can we form three groups of people from 5 people, with each of the two groups consisting of 2 people, and the last group with only one person?\r
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document.write( "In how many ways can we form 4 groups of people from 11 people, where one group consists of 4 people, another group has 3 people, and each of the two remaining groups consisting of 2 people?\r
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document.write( "The order of the grouping doesn't matter. \n" );
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Algebra.Com's Answer #286116 by sudhanshu_kmr(1152)![]() ![]() You can put this solution on YOUR website! 1) \n" ); document.write( "no. of ways to arrange 5 people on 3 groups = 5C2 * 3C2 * 1C1 / 2! = 15 \r \n" ); document.write( "\n" ); document.write( "here two groups has 2 people each and order of the grouping doesn't matter.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "2) \n" ); document.write( "no. of ways to make a group of 4 people from 11= 11C4\r \n" ); document.write( "\n" ); document.write( "no. of ways to make a group of 3 people from remaining 7 = 7C3\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "no. of ways to make a group of 2 people from remaining 4 = 4C2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "no. of ways to make a group of 2 people from remaining 2 = 2C2\r \n" ); document.write( "\n" ); document.write( "and here 2 groups of 2 people and order of group doesn't matter \r \n" ); document.write( "\n" ); document.write( "no. of ways to arrange 11 people on 4 groups = 11C4 * 7C3 * 4C2 * 2C2 /2!\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "= 34650\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "try to understand the concept and solve it yourself.... \n" ); document.write( " \n" ); document.write( " |