document.write( "Question 404758: Suppose you have a group of six men and three women; you want to line them up so that no two women are standing next to each other. In how many ways can this be done?\r
\n" ); document.write( "\n" ); document.write( "I know there has to be an easier way to figure this out than to just write M/F in combination until all of the combination's are exhausted (which is the method my classmates have done, and they have answers ranging from 12 to 30 ways) - we just have not gone over the actual formulas for this, and I can't figure it out from the textbook.
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Algebra.Com's Answer #286113 by sudhanshu_kmr(1152)\"\" \"About 
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\n" ); document.write( "no. of ways to arrange 6 men = 6P6 = 6! \r
\n" ); document.write( "\n" ); document.write( "# M # M # M # M # M # M # \r
\n" ); document.write( "\n" ); document.write( "any women can be put at place # . \r
\n" ); document.write( "\n" ); document.write( "total no. of place= 7\r
\n" ); document.write( "\n" ); document.write( "no. of ways to put 3 women at 7 places = 7P3 = 210\r
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\n" ); document.write( "\n" ); document.write( "total no. of ways to arrange 6 men and 3 women = 151200\r
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\n" ); document.write( "\n" ); document.write( "here the concept is : \r
\n" ); document.write( "\n" ); document.write( "there is no restriction with men so firstly arrange men and after arranging them \r
\n" ); document.write( "\n" ); document.write( "at N places, arrange the women at (N+1)places....
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