document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404861>Question 404861</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve:\r<BR>\n" );
document.write( "\n" );
document.write( "log(x+1) + log(x-1) = log 48 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286090 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286090\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve: <BR>\n" );
document.write( "log(x+1) + log(x-1) = log 48\r<BR>\n" );
document.write( "\n" );
document.write( "..\r<BR>\n" );
document.write( "\n" );
document.write( "log(x+1) + log(x-1)-log 48 = 0<BR>\n" );
document.write( "log(x+1)(x-1)/48=0<BR>\n" );
document.write( "change to exponential form<BR>\n" );
document.write( "10^0=(x+1)(x-1)/48<BR>\n" );
document.write( "1=(x+1)(x-1)/48<BR>\n" );
document.write( "x^2-1=48<BR>\n" );
document.write( "x=sqrt(49)<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( "x=-7 (reject, x>-1) </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );