document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404787>Question 404787</A>: <I><SPAN STYLE=\"word-break: break-all;\"> x+y=19<BR>\n" );
document.write( "x-y=-7   how do u do this by elimination<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286080 by </B><A HREF=/tutors/aboutme.mpl?userid=keksjr><B>keksjr(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=keksjr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=keksjr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286080\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> taking x+y=19 to be eqtn I and<BR>\n" );
document.write( "       x-y=-7 to be eqtn II<BR>\n" );
document.write( "if x and y have coefficients, you will have to choose from the two unknown x and y, which one to eliminate first by using the coefficient in either eqtn I or eqtn II to multiple all through what's on eqtn II and same to eqtn I respectively.\r<BR>\n" );
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document.write( "But since there is no coefficient there on the two variables, the add x to eliminate y: By doing so, you have;\r<BR>\n" );
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document.write( "add \"x and x = 2x\" , \"+y and -y = 0\", \"19 and -7 = 12\"<BR>\n" );
document.write( "      2x+0=12, 2x=12, x=6.\r<BR>\n" );
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document.write( "substitute \"x\" in any of the 2 above eqtn but lets use eqtn I to find y:<BR>\n" );
document.write( "    x+y=19<BR>\n" );
document.write( "    6+y=19<BR>\n" );
document.write( "      y=19-6<BR>\n" );
document.write( "      y=13<BR>\n" );
document.write( "     <BR>\n" );
document.write( "      (x,y) (6,13)\r<BR>\n" );
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