document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43592>Question 43592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am very confussed on a problem, I barel even know where to start. <BR>\n" );
document.write( "A/BH = 1/2 I am solving for H. I am very confussed, I know the LCD must be 2BH. I am just wondering how I am going about this. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28607 by </B><A HREF=/tutors/aboutme.mpl?userid=aaaaaaaa><B>aaaaaaaa(138)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=aaaaaaaa><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28607\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You need to isolate H. To do that, you multiply both numbers on the top so that the bottom matches the LCM, 2BH. Watch:\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A%2FBH+=+1%2F2 ALIGN=MIDDLE  ALT=\"A%2FBH+=+1%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%2AA%2F2BH+=+1%2ABH%2F2BH ALIGN=MIDDLE  ALT=\"2%2AA%2F2BH+=+1%2ABH%2F2BH\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2A+=+BH ALIGN=MIDDLE  ALT=\"2A+=+BH\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2A%2FB+=+H ALIGN=MIDDLE  ALT=\"2A%2FB+=+H\"   DISABLED_style= \"max-width:90%; height:auto;\" > </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );