document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404019>Question 404019</A>: <I><SPAN STYLE=\"word-break: break-all;\"> a rectangle has a perimeter of 74 inches. the length of one side is 3X-1.<BR>\n" );
document.write( "the width of one side is 2X+3. What is the area? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286065 by </B><A HREF=/tutors/aboutme.mpl?userid=keksjr><B>keksjr(7)</B></A><img src=\"/images/stars/stars-05.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=keksjr><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=keksjr><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286065\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of a Rectangle is A=LW and the Perimeter of a Rectangle is P=2L+2W<BR>\n" );
document.write( "Therefore; L=3X-1, and W=2X+3, P=74,  <BR>\n" );
document.write( "P=2L+2W<BR>\n" );
document.write( "74=2(3X-1)+2(2X+3)<BR>\n" );
document.write( "74=6X-2+4X+6<BR>\n" );
document.write( "74=10X+4<BR>\n" );
document.write( "74-4=10X<BR>\n" );
document.write( "X=7. finding the value of L and W; 2L=2(3X-1),<BR>\n" );
document.write( "                                   2L=2[3(7)-1]<BR>\n" );
document.write( "                                    L=20 in.<BR>\n" );
document.write( "  2W=2(2X+3)<BR>\n" );
document.write( "  2W=2[2(7)+3]<BR>\n" );
document.write( "   W=17 in.\r<BR>\n" );
document.write( "\n" );
document.write( "Area of the Rectangle A=LW, A = 20x17 = 340sq.in </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );