document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404717>Question 404717</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (0,0) x = -3y - 12 find an equation of the line that passes through the given point and is perpendicular to the given line. write the equation in slope intercept form. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286052 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286052\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (0,0) x = -3y - 12 \r<BR>\n" );
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document.write( "x = -3y - 12 <BR>\n" );
document.write( "3y=-x-12<BR>\n" );
document.write( "/3<BR>\n" );
document.write( "y=-x/3 -4<BR>\n" );
document.write( "compare with y= mx+b\r<BR>\n" );
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document.write( "m= slope = -1/3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "The perpendicular line will have slope 3<BR>\n" );
document.write( "..<BR>\n" );
document.write( "since the line passes through(0,0) the y intercepr = -12. b=-12<BR>\n" );
document.write( "y=3x-12 is the equation\r<BR>\n" );
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document.write( "...<BR>\n" );
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document.write( " </SPAN>\n" );
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