document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404678>Question 404678</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 50 mph. At 11:00 a.m., a second truck leaves along the same route, traveling at 75 mph. When will the second truck catch up to the first? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #286036 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=286036\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 9:00 a.m. a truck leaves the truck yard and travels west at a rate of 50 mph. At 11:00 a.m., a second truck leaves along the same route, traveling at 75 mph. When will the second truck catch up to the first?<BR>\n" );
document.write( "------------------------<BR>\n" );
document.write( "The 1st truck is 100 miles away (50 x 2)<BR>\n" );
document.write( "The 2nd truck gains on the 1st at 25 mph (75- 50)<BR>\n" );
document.write( "100/25 = 4 hours<BR>\n" );
document.write( "11:00 + 4 = 1500 hours\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );