document.write( "Question 404753: find the slope intercept form of the equation of the line that passs thought (-1,5)and is parallel to 4x+2y=8 \n" ); document.write( "
Algebra.Com's Answer #286031 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "find the slope intercept form of the equation of the line that passes thought (\"-1%2C5\")and is \"parallel\" to \"4x%2B2y=8\"\r
\n" ); document.write( "\n" ); document.write( "first find the slope of this line:\r
\n" ); document.write( "\n" ); document.write( "\"4x%2B2y=8\"......write it in slope-intercept form...or solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"2y=+-+4x+%2B+8\".......both sides divide by \"2\"\r
\n" ); document.write( "\n" ); document.write( "\"2y%2F2=+-+4x%2F2+%2B+8%2F2\"\r
\n" ); document.write( "\n" ); document.write( "\"y=+-2x+%2B+4\".........as you can see, slope is \"-2\"\r
\n" ); document.write( "\n" ); document.write( "since the line that passes thought (\"-1%2C5\") is \"parallel\" to given line, should have \"same\" slope\r
\n" ); document.write( "\n" ); document.write( "now, we have slope \"m=-2\" and point (\"-1%2C5\") and we can find the equation of the line that passes thought\r
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Solved by pluggable solver: FIND a line by slope and one point

\n" ); document.write( " What we know about the line whose equation we are trying to find out:
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  • it goes through point (-1, 5)

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  • it has a slope of -2

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\n" ); document.write( " First, let's draw a diagram of the coordinate system with point (-1, 5) plotted with a little blue dot:
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\n" ); document.write( " Write this down: the formula for the equation, given point \"x%5B1%5D%2C+y%5B1%5D\" and intercept a, is
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\n" ); document.write( " \"y=ax+%2B+%28y%5B1%5D-a%2Ax%5B1%5D%29\" (see a paragraph below explaining why this formula is correct)
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\n" ); document.write( " Given that a=-2, and \"system%28+x%5B1%5D+=+-1%2C+y%5B1%5D+=+5+%29+\", we have the equation of the line:
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\n" ); document.write( " \"y=-2%2Ax+%2B+3\"
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\n" ); document.write( " Explanation: Why did we use formula \"y=ax+%2B+%28y%5B1%5D+-+a%2Ax%5B1%5D%29\" ? Explanation goes here. We are trying to find equation y=ax+b. The value of slope (a) is already given to us. We need to find b. If a point (\"x%5B1%5D\", \"y%5B1%5D\") lies on the line, it means that it satisfies the equation of the line. So, our equation holds for (\"x%5B1%5D\", \"y%5B1%5D\"): \"y%5B1%5D+=+a%2Ax%5B1%5D%2Bb\" Here, we know a, \"x%5B1%5D\", and \"y%5B1%5D\", and do not know b. It is easy to find out: \"b=y%5B1%5D-a%2Ax%5B1%5D\". So, then, the equation of the line is: \"+y=ax%2B%28y%5B1%5D-a%2Ax%5B1%5D%29+\".
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\n" ); document.write( " Here's the graph:
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\n" ); document.write( "\n" ); document.write( "now, let see a graph with both lines on it:\r
\n" ); document.write( "\n" ); document.write( "\"y=+-2x+%2B+4\"\r
\n" ); document.write( "\n" ); document.write( "\"y=-2x%2B3\"\r
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\n" ); document.write( "\n" ); document.write( "\"+graph%28+500%2C500%2C+-10%2C+10%2C+-10%2C+10%2C+-2x+%2B+4%2C-2x%2B3%29+\"\r
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