document.write( "Question 43599This question is from textbook Algebra and trigonometry with analytic geometry
\n" ); document.write( ": The table shows several value of the function f(x)= -x^3+x^2-x+2. Complete the missing values in this table, and then use these values and the intermediate vaule theorem to determine (an) interval(s) where the function must have zero.\r
\n" ); document.write( "\n" ); document.write( "x -2 -1 0 1 2
\n" ); document.write( "f(x) 16 -4\r
\n" ); document.write( "\n" ); document.write( "My answer is (0,1) u (2,infty) but unsure. thanks as always for the help.
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Algebra.Com's Answer #28603 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
f(x)= -x^3+x^2-x+2.\r
\n" ); document.write( "\n" ); document.write( "x -2 -1 0 1 2
\n" ); document.write( "f(x) 16 -4\r
\n" ); document.write( "\n" ); document.write( "Your f(-1), f(0), and f(1) are all positive.
\n" ); document.write( "Your f(2) is negative.
\n" ); document.write( "Since the function is continuous in the interval x=1 to x=2
\n" ); document.write( "The graph must cross the x-axis to get from + to -
\n" ); document.write( "Therefore there must be a zero between x=1 and x=2.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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