document.write( "Question 404715: Solve for X in the following proportion:
\n" ); document.write( "\"%281%2F2%29%3AX=3%3A12\"
\n" ); document.write( "

Algebra.Com's Answer #286025 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"%281%2F2%29%3AX=3%3A12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "We want the \"1%2F2\" to be 3. So we can multiply it by 6 to get \"6%281%2F2%29=6%2F2=3\". However, we have to do this with X as well to get \r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"3%3A3x=3%3A12\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Since the first two terms are equal to 3, this means that the second terms are equal. So \"3x=12\", which means that \"x=4\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "If you need more help, email me at jim_thompson5910@hotmail.com\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, please consider visiting my website: http://www.freewebs.com/jimthompson5910/home.html and making a donation. Thank you\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Jim
\n" ); document.write( "
\n" );