document.write( "Question 404734: In square ABCD, diagonal AC has a slope of -2/5. what is the slope of diagonal BD? \n" ); document.write( "
Algebra.Com's Answer #286015 by MathLover1(20849)\"\" \"About 
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the two diagonals in a square are at \"right\"\"+angles\" to each other;\r
\n" ); document.write( "\n" ); document.write( " hence if one diagonal has a \"slope+=+-+%28+2%2F5+%29\", the other must have \"slope+=+%2B+%28+5%2F2+%29\"\r
\n" ); document.write( "\n" ); document.write( "Explanation:\r
\n" ); document.write( "\n" ); document.write( " We know that \"if+\"\"two+\"\"lines\" are at right angles to each other, \"product\" of their slopes \"must\" be equal to \"%28+-+1+%29\". \r
\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"-%282%2F5%29%28+5%2F2+%29=%28-%282%2A5%29%29%2F%285%2A2%29+=+-10%2F10=-1\"\r
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\n" ); document.write( "\n" ); document.write( "hence slope of the other diagonal \"+BD+=+5%2F2\"\r
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