document.write( "Question 404691: Please help me solve this equation the sum of two consecutive integers is 19 less than their product. find the integers. \n" ); document.write( "

Algebra.Com's Answer #285987 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "two consecutive integers
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document.write( "Let x and (x+1) represent the two consecutive integers
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document.write( "Question states***
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document.write( " x +(x+1)= x(x+1)-19
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document.write( "Solving for x
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document.write( " 2x + 1 = x^2 + x - 19
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document.write( "  x^2 -x - 20 = 0 
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document.write( "factoring
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document.write( " (x-5)(x+4)= 0 Note:SUM of the inner product(-5x) and the outer product(4x) = -x
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document.write( "(x-5)=0   x = 5, the two consecutive integers are 5 and 6
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document.write( "(x+4)= 0  x = -4 the two consecutive integers are -4 and -3\r
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document.write( "CHECKING our Answer(s)***
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document.write( " 5 + 6 = 30 - 19
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document.write( " -4 - 3 = -4*-3 - 19 \n" );
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