document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404642>Question 404642</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A solution of 60 ml is 50% acid. How many ml of water must be added to create a 30% acid solution?\r<BR>\n" );
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document.write( "I tried solving this problem but got a negative answer...\r<BR>\n" );
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document.write( "I put the question in this form-  W+.50(60)=.30(W+60)  \r<BR>\n" );
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document.write( "Thank you. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285960 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285960\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A solution of 60 ml is 50% acid. How many ml of water must be added to create a 30% acid solution? <BR>\n" );
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document.write( "60 ml of 50% has 30 ml of acid.<BR>\n" );
document.write( "For 30 ml to be 30%, the total must be 100 ml<BR>\n" );
document.write( "Add 40 ml of water.<BR>\n" );
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document.write( "You can do it this way:<BR>\n" );
document.write( "T = w + 60  (total solution)<BR>\n" );
document.write( "0.5*60 + w*0 = 0.3(w + 60)  (total acid)<BR>\n" );
document.write( "30 = 0.3w + 18<BR>\n" );
document.write( "0.3w = 12<BR>\n" );
document.write( "w = 40 ml </SPAN>\n" );
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