document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404651>Question 404651</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A total of $4500 was invested, part of it at 6% interest and the remainder at 12%. If the total yearly interest amounted to $315, how much was invested at each rate? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285959 by </B><A HREF=/tutors/aboutme.mpl?userid=subudear><B>subudear(62)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=subudear><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285959\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x amount be at 6% then (4500 -x ) amount will be at 12%\r<BR>\n" );
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document.write( "so\r<BR>\n" );
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document.write( "(6/100)x + (12/100)(4500-x) = 315\r<BR>\n" );
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document.write( "6x + 12(4500-x) = 31500\r<BR>\n" );
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document.write( "6x + 54000 -12x = 31500\r<BR>\n" );
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document.write( "-6x = -22500\r<BR>\n" );
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document.write( "x = 3750\r<BR>\n" );
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document.write( "so 3750 amount was at 6% and 750 was given at 12% rate </SPAN>\n" );
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