document.write( "Question 404592: The perimeter of a rectangular field is 504 yards. It's length is 6 yards shorter than twice it's width? What is the area? \n" ); document.write( "
Algebra.Com's Answer #285939 by algebrahouse.com(1659)\"\" \"About 
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\"The perimeter of a rectangular field is 504 yards. It's length is 6 yards shorter than twice it's width? What is the area?\"\r
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\n" ); document.write( "\n" ); document.write( "x = width
\n" ); document.write( "2x - 6 = length {six yards shorter than twice the width}\r
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\n" ); document.write( "\n" ); document.write( "2(x) + 2(2x - 6) = 504 {two times width + two times length = perimeter}
\n" ); document.write( "2x + 4x - 12 = 504 {used distributive property}
\n" ); document.write( "6x - 12 = 504 {combined like terms}
\n" ); document.write( "6x = 516 {added 12 to both sides}
\n" ); document.write( "x = 86 {divided both sides by 6}
\n" ); document.write( "2x - 6 = 166 {substituted 86 for x into 2x - 6}\r
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\n" ); document.write( "\n" ); document.write( "width = 86 yards
\n" ); document.write( "length = 166 yards
\n" ); document.write( "area = 14,276 yds^2 {area is length x width}
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