document.write( "Question 404584: How many gallons of a 3% salt solution must be mixed with 10 gallons of a 8% solution to obtain a 4% solution \n" ); document.write( "

Algebra.Com's Answer #285920 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"a\"$ = gallons of 3% solution needed
\n" ); document.write( "In words:
\n" ); document.write( "(gallons of salt in final solution)/(total final solution) = 4%
\n" ); document.write( "given:
\n" ); document.write( " $\".03a\"$ = gallons of salt in 3% solution
\n" ); document.write( " $\".08%2A10+=+.8\"$ = gallons of salt in 8% solution
\n" ); document.write( "-------------------------------------
\n" ); document.write( " $\"%28.03a+%2B+.8%29%2F%28a+%2B+10%29+=+.04\"$
\n" ); document.write( " $\".03a+%2B+.8+=+.04%2A%28a+%2B+10%29\"$
\n" ); document.write( " $\".03a+%2B+.8+=+.04a+%2B+.4\"$
\n" ); document.write( " $\".01a+=+.4\"$
\n" ); document.write( " $\"a+=+40\"$ gallons
\n" ); document.write( "40 gallons of a 3% solution must be added
\n" ); document.write( "check answer:
\n" ); document.write( " $\"%28.03a+%2B+.8%29%2F%28a+%2B+10%29+=+.04\"$
\n" ); document.write( " $\"%28.03%2A40+%2B+.8%29%2F%2840+%2B+10%29+=+.04\"$
\n" ); document.write( " $\"%281.2+%2B+.8%29%2F50+=+.04\"$
\n" ); document.write( " $\"2%2F50+=+.04\"$
\n" ); document.write( " $\"2+=+50%2A.04\"$
\n" ); document.write( " $\"2+=+2\"$
\n" ); document.write( "OK \n" ); document.write( "

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