document.write( "Question 404571: A is twice as old as B was 2 years ago. If the differance in their ages be 6 years. Find A's age ? \n" ); document.write( "

Algebra.Com's Answer #285911 by josmiceli(19441) $\"\"$ $\"About$

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Given:
\n" ); document.write( "Let $\"A\"$ = A's age now
\n" ); document.write( "Let $\"B\"$ = B's age now
\n" ); document.write( "Then $\"B-2\"$ = B's age 2 years ago
\n" ); document.write( "given:
\n" ); document.write( "(1) $\"A+=+2%2A%28B+-+2%29\"$
\n" ); document.write( "(2) $\"A+-+B+=+6\"$
\n" ); document.write( "----------------
\n" ); document.write( "from (1):
\n" ); document.write( "(1) $\"A+=+2B+-+4\"$
\n" ); document.write( "(1) $\"A+-+2B+=+-4\"$
\n" ); document.write( "(1) $\"-A+%2B+2B+=+4\"$
\n" ); document.write( "Now add (1) and (2)
\n" ); document.write( "(1) $\"-A+%2B+2B+=+4\"$
\n" ); document.write( "(2) $\"A+-+B+=+6\"$
\n" ); document.write( " $\"B+=10\"$
\n" ); document.write( "And, from (2),
\n" ); document.write( "(2) $\"A+-+B+=+6\"$
\n" ); document.write( "(2) $\"A+-+10+=+6\"$
\n" ); document.write( "(2) $\"A+=+16\"$
\n" ); document.write( "A is 16 now
\n" ); document.write( "check answer:
\n" ); document.write( "(1) $\"A+=+2%2A%28B+-+2%29\"$
\n" ); document.write( "(1) $\"16+=+2%2A%2810+-+2%29\"$
\n" ); document.write( "(1) $\"16+=+2%2A8\"$
\n" ); document.write( " $\"16+=+16\"$
\n" ); document.write( "OK \n" ); document.write( "

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