document.write( "Question 404563: 1. it takes one guy 5 hours to paint a house, another guy 3 hrs, and the last guy 2 hrs to paint the same house if they work together how long will it take them to paint the house.\r
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document.write( "2. It takes 3 hours for an open valve to fill a tank and 4.5 hours for a valve to empty the tank. How long would it take to fill the tank if both valves are open. \n" );
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Algebra.Com's Answer #285906 by stanbon(75887) ![]() You can put this solution on YOUR website! I'll do the 1st one. The 2nd uses the same method. \n" ); document.write( "---- \n" ); document.write( "1. it takes one guy 5 hours to paint a house, another guy 3 hrs, and the last guy 2 hrs to paint the same house if they work together how long will it take them to paint the house. \n" ); document.write( "--- \n" ); document.write( "1st guy DATA: \n" ); document.write( "time = 5 hrs/job ; rate = 1/5 job/hr \n" ); document.write( "2nd guy DATA: \n" ); document.write( "time = 3 hrs/job ; rate = 1/3 job/hr \n" ); document.write( "3rd guy DATA: \n" ); document.write( "time = 2 hrs/job ; rate = 1/2 job/hr \n" ); document.write( "---- \n" ); document.write( "Together data: \n" ); document.write( "time = x hrs/job ; rate = 1/x job/hr \n" ); document.write( "==== \n" ); document.write( "Equation: \n" ); document.write( "rate + rate + rate = together rate \n" ); document.write( "1/5 + 1/3 + 1/2 = 1/x \n" ); document.write( "Multiply thru by 30x to get: \n" ); document.write( "6x + 10x + 15x = 30 \n" ); document.write( "31x = 30 \n" ); document.write( "x = 30/31 hrs to do the job together. \n" ); document.write( "x = (30/31)(60 min) = 58.06 minutes \n" ); document.write( "========= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "========= \n" ); document.write( "2. It takes 3 hours for an open valve to fill a tank and 4.5 hours for a valve to empty the tank. How long would it take to fill the tank if both valves are open. \n" ); document.write( " \n" ); document.write( " |