document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404555>Question 404555</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Dave and Jane Wells have a new rectangle driveway.  The perimeter of the driveway is 168 feet.  The length is 12 feet longer then three times the width.  What are the dimensions of the driveway? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285901 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285901\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Dave and Jane Wells have a new rectangle driveway.  The perimeter of the driveway is 168 feet.  The length is 12 feet longer then three times the width.  What are the dimensions of the driveway?<BR>\n" );
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document.write( "Let w = width<BR>\n" );
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document.write( "3w+12 = length<BR>\n" );
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document.write( "2(w + 3w+12) = 168<BR>\n" );
document.write( "2(4w+12) = 168<BR>\n" );
document.write( "(4w+12) = 84<BR>\n" );
document.write( "4w = 72<BR>\n" );
document.write( "w = 13 feet (width)<BR>\n" );
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document.write( "Length:<BR>\n" );
document.write( "3w+12 = 3(13)+12 = 39+12 = 51 feet\r<BR>\n" );
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