document.write( "Question 404408: a passenger train leaves a train station four hours after a train leaves the same station. The freight train is traveling ten mph slower than the passenger train. Find the rate of the passenger train if the passenger train overtakes the fright train in 20 hours. \n" ); document.write( "
Algebra.Com's Answer #285882 by mananth(16946)\"\" \"About 
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a passenger train leaves a train station four hours after a train leaves the same station. The freight train is traveling ten mph slower than the passenger train. Find the rate of the passenger train if the passenger train overtakes the fright train in 20 hours.
\n" ); document.write( "..
\n" ); document.write( "Passenger train x mph
\n" ); document.write( "freight train x-10 mph
\n" ); document.write( "...
\n" ); document.write( "In fours hours freight train has traveled 4(x-10) hours
\n" ); document.write( ",..\r
\n" ); document.write( "\n" ); document.write( "Catch up distance = 4(x-10)\r
\n" ); document.write( "\n" ); document.write( "catch up speed = 10 mph\r
\n" ); document.write( "\n" ); document.write( "Time = distance / speed
\n" ); document.write( "4(x-10)/10= 20
\n" ); document.write( "4x-40=200
\n" ); document.write( "4x=240
\n" ); document.write( "x=60 mph.
\n" ); document.write( "Speed of passenger train = 60 mph\r
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