document.write( "Question 404530: the area of a rectangle is 96 square centimeters. if the width of the rectangle is 4 centimeter less than its length, what are the dimension of the rectangle \n" ); document.write( "
Algebra.Com's Answer #285876 by mananth(16946)\"\" \"About 
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length= x
\n" ); document.write( "width = x-4
\n" ); document.write( "...
\n" ); document.write( "area = L*W
\n" ); document.write( "Area = x(x-4)=96
\n" ); document.write( "x^2-4x=96
\n" ); document.write( "x^2-4x-96=0
\n" ); document.write( "x^2-12x+8x-96=0
\n" ); document.write( "x(x-12)+8(x-12)=0
\n" ); document.write( "*x-12)(x+8)=0
\n" ); document.write( "So x= 12 cms===>length
\n" ); document.write( "width = 12-4=8 cm
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