document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404399>Question 404399</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A runner starts a race at the starting line. A second runner starts at 44 yards. If the first runner moves 7 yards each second and the second runner moves 3 yards each second, at what distance will the first runner catch the second runner? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285857 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285857\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A runner starts a race at the starting line. A second runner starts at 44 yards. If the first runner moves 7 yards each second and the second runner moves 3 yards each second, at what distance will the first runner catch the second runner?\r<BR>\n" );
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document.write( "let x = distance the first runner traveled<BR>\n" );
document.write( "then x-44 = distance the second runner traveled\r<BR>\n" );
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document.write( "time traveled = distance/speed<BR>\n" );
document.write( "Both traveled the same amount of time<BR>\n" );
document.write( "x/7=(x-44)/3<BR>\n" );
document.write( "3x=7x-(7)(44)<BR>\n" );
document.write( "-4x=-(7)(44)<BR>\n" );
document.write( "x=77 yards<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "The first runner will have traveled a distance of 77 yards to catch up with the second runner </SPAN>\n" );
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