document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404480>Question 404480</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 10.   A square has a 40-cm diagonal. How long is each side of the square? Round your answer to the nearest tenth of a centimeter.  (1 point </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285844 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285844\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The legs and the diagonal form a right angle.<BR>\n" );
document.write( "The diagonal is the hypotenuse.<BR>\n" );
document.write( "apply Pythagoras theorem<BR>\n" );
document.write( "..<BR>\n" );
document.write( "Let l be one leg. <BR>\n" );
document.write( "since it is a square the other leg is also l.\r<BR>\n" );
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document.write( "l^2+l^2= 40^2<BR>\n" );
document.write( "2l^2=1600<BR>\n" );
document.write( "l^2=800<BR>\n" );
document.write( "l = sqrt (800)<BR>\n" );
document.write( "l = 28.28<BR>\n" );
document.write( "...<BR>\n" );
document.write( "l= 28.3 cm<BR>\n" );
document.write( " </SPAN>\n" );
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