document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404455>Question 404455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How much of an alloy that is 20% copper should be mixed with 300 oz of an alloy that is 80% copper to get an alloy that is 40% copper?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285826 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285826\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 0.20x + 0.80*300 = 0.40*(x + 300)<BR>\n" );
document.write( "==> 0.20x + 240 = 0.40x + 120<BR>\n" );
document.write( "==> 120 = 0.20x<BR>\n" );
document.write( "==> x = 600 oz of the 20% copper alloy should be added. </SPAN>\n" );
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