document.write( "Question 43586: Graph y> or = √(3x+12). \n" ); document.write( "

Algebra.Com's Answer #28582 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"y+%3E=+sqrt%283x+%2B+12%29\"$
\n" ); document.write( "*sorry, the graph doesn't extend all the way to (-4,0)
\n" ); document.write( " $\"+graph%28+600%2C+600%2C+-10%2C+10%2C+-10%2C+10%2C+sqrt%283x+%2B+12%29+%29+\"$
\n" ); document.write( "Limitation To Domain:
\n" ); document.write( "A real number squared will not give you a negative number, so:
\n" ); document.write( " $\"3x+%2B+12+%3E=+0\"$
\n" ); document.write( " $\"3x+%3E=+-12\"$
\n" ); document.write( " $\"x+%3E=+-4\"$
\n" ); document.write( "Vertex: (-4,f(x)) = (-4,0)
\n" ); document.write( "Shading:
\n" ); document.write( "If you pick the point: (-4,1)
\n" ); document.write( "You get: $\"1+%3E+0\"$ which is correct
\n" ); document.write( "You would shade only above the solid line, not to the left or under it.
\n" ); document.write( "If it helps you, you can draw a vertical line at $\"x+=+4\"$ . Shade above the graphed square root line and to the right of the vertical line. \n" ); document.write( "

\n" );