document.write( "Question 404226: Train A and B are traveling in the same direction on parallel tracks. Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour. Train A passes a station at 8:10 AM. If train B passes the same station at 8:40 am, what time will train B catch up to train A? \n" ); document.write( "
Algebra.Com's Answer #285816 by ankor@dixie-net.com(22740)\"\" \"About 
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Train A and B are traveling in the same direction on parallel tracks.
\n" ); document.write( " Train A is traveling at 80 miles per hour and train B is traveling at 88 miles per hour.
\n" ); document.write( " Train A passes a station at 8:10 AM. If train B passes the same station at
\n" ); document.write( " 8:40 am, what time will train B catch up to train A?
\n" ); document.write( ":
\n" ); document.write( "from the given information, we know that train B is 30 min (1/2 hr) behind
\n" ); document.write( " train A, when train A passes the station
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\n" ); document.write( "The distance between the trains at this time: \"1%2F2\" * 88 = 44 mi
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\n" ); document.write( "Let t = time required for train B to catch train a
\n" ); document.write( ":
\n" ); document.write( "write a distance equation: Dist = speed * time
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\n" ); document.write( "Train B travel dist = Train A travel dist + 44 mi
\n" ); document.write( "88t = 80t + 44
\n" ); document.write( "88t - 80t = 44
\n" ); document.write( "8t = 44
\n" ); document.write( "t = \"44%2F8\"
\n" ); document.write( "t = 5.5 hr or 5 hr 30 min
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\n" ); document.write( "8:10 AM + 5:30 = 1:30 pm, B catches A
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\n" ); document.write( "Feedback to Student comment. \"I figure it to be 1:40, are you sure about your answer?\"
\n" ); document.write( ":
\n" ); document.write( "Check solution of 5.5 hrs,
\n" ); document.write( ":
\n" ); document.write( "Train B should travel 44 mi more that Train A in the same time
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\n" ); document.write( "Train B: 88 * 5.5 = 484 mi
\n" ); document.write( "Train A: 80 * 5.5 = 440 mi
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\n" ); document.write( "Difference in dist: 44 mi
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