document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404450>Question 404450</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I need help with this problem: A pound of tin is worth $1 more than a pound of copper. Three pounds of tin are mixed with 7 pounds of copper to make bronze that sells for $3.05 per pound. How much is a pound of tin worth? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285804 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285804\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A pound of tin is worth $1 more than a pound of copper. Three pounds of tin are mixed with 7 pounds of copper to make bronze that sells for $3.05 per pound. How much is a pound of tin worth?<BR>\n" );
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document.write( "Let copper be worth $x per pound<BR>\n" );
document.write( "Then tin is worth $(x+1) per pound.<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "Value Equation: 3(x+1) + 7x = 3.05*10<BR>\n" );
document.write( "3x+3 + 7x = 30.50<BR>\n" );
document.write( "10x = 27.50<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x = $2.75 (price of a pound of copper)<BR>\n" );
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document.write( "x+1 = $3.75 (price of a pound of tin)<BR>\n" );
document.write( "======================================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============ </SPAN>\n" );
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