document.write( "Question 404371: (1+sqroot50)*(1+sqroot50)= 1+2sqroot50+50= 51+2sqroot50= 51+7sqroot2\r
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Algebra.Com's Answer #285770 by Tatiana_Stebko(1539) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"%28a%2Bb%29%2A%28a%2Bb%29=%28a%2Bb%29%5E2\"$
\n" ); document.write( "Formula $\"%28a%2Bb%29%5E2=a%5E2%2B2ab%2Bb%5E2\"$
\n" ); document.write( "Thats why $\"%281%2Bsqrt%2850%29%29%2A%281%2Bsqrt%2850%29%29=1%2B2sqrt%2850%29%2B50\"$ is correct.
\n" ); document.write( " $\"1%2B2sqrt%2850%29%2B50=51%2B2sqrt%2850%29\"$ is correct,
\n" ); document.write( "but

\n" ); document.write( "So $\"51%2B2sqrt%2850%29=51%2B10sqrt%282%29\"$ \n" ); document.write( "

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