document.write( "Question 43582: State the number of positive real zeros, negative real zeros, and imaginary zeros for g(x)=9x^3-7x^2+10x-4. \n" ); document.write( "

Algebra.Com's Answer #28577 by Nate(3500) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"g%28x%29+=+9x%5E3+-+7x%5E2+%2B+10x+-+4\"$
\n" ); document.write( "Look at the value coefficients: +9 then -7 then +10 then -4
\n" ); document.write( "The sign changes three times, so you have a chance of three positive real roots.
\n" ); document.write( " $\"g%28-x%29+=+9%28-x%29%5E3+-+7%28-x%29%5E2+%2B+10%28-x%29+-+4\"$
\n" ); document.write( " $\"g%28-x%29+=+-9x+-+7x+-+10x+-+4\"$
\n" ); document.write( "Look at the value coefficients: -9 then -7 then -10 then -4
\n" ); document.write( "The sign never changes, so you obviously know that there are absolutely no negative real roots.
\n" ); document.write( "Pos: .. 3 .. 1
\n" ); document.write( "Neg: . 0 .. 0
\n" ); document.write( "Imag: 0 .. 2
\n" ); document.write( "You can take two away from the positives and add to the imaginery. \n" ); document.write( "

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