document.write( "Question 404271: Distance and time: Two athletes are jogging in the same direction along an exercise path. After x minutes the first athletes distance in miles from a parking lot is given by 1/6x and the second athletes distance is given by 1/8x + 2.\r
\n" ); document.write( "\n" ); document.write( " (a) When are the athletes the same distance from the parking lot?\r
\n" ); document.write( "\n" ); document.write( " (b) When is the first athlete farther away from the parking lot than the second?
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #285763 by ankor@dixie-net.com(22740)\"\" \"About 
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Two athletes are jogging in the same direction along an exercise path.
\n" ); document.write( " After x minutes the first athletes distance in miles from a parking lot is
\n" ); document.write( "given by \"1%2F6\"x and the second athletes distance is given by \"1%2F8\"x + 2.
\n" ); document.write( ":
\n" ); document.write( "(a) When are the athletes the same distance from the parking lot?
\n" ); document.write( "\"1%2F6\"x = \"1%2F8\"x + 2
\n" ); document.write( "\"1%2F6\"x - \"1%2F8\"x = 2
\n" ); document.write( "Common denominator is 24
\n" ); document.write( "\"4%2F24\"x - \"3%2F24\"x = 2
\n" ); document.write( "\"1%2F24\"x = 2
\n" ); document.write( "Multiply both sides by 24
\n" ); document.write( "1x = 24(2)
\n" ); document.write( "x = 48 minutes
\n" ); document.write( ":
\n" ); document.write( "We can check this:
\n" ); document.write( "\"1%2F6\"(48) = \"1%2F8\"(48) + 2
\n" ); document.write( ":
\n" ); document.write( ":
\n" ); document.write( "(b) When is the first athlete farther away from the parking lot than the second?
\n" ); document.write( "\"1%2F24\"x > 2
\n" ); document.write( "x > 48 minutes, Say 49 minutes
\n" ); document.write( "\"1%2F6\"(49) = 8.167 mi
\n" ); document.write( "\"1%2F8\"(49) + 2 = 8.125 mi \n" ); document.write( "
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