document.write( "Question 404276: How do I solve the following:\r
\n" ); document.write( "\n" ); document.write( "Assume that Log 4 ≈ 0.602, log 5 ≈ 0.699 and log6 ≈0.778.
\n" ); document.write( "Use the properties of logarithms to evaluate the expression:
\n" ); document.write( "Log24
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Algebra.Com's Answer #285728 by MathLover1(20850) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Step 1\r
\n" ); document.write( "\n" ); document.write( "Rewrite $\"24\"$ as a product of $\"4\"$ and $\"6\"$ .\r
\n" ); document.write( "\n" ); document.write( "= $\"log+%284+%2A+6%29\"$ \r
\n" ); document.write( "\n" ); document.write( "Step 2\r
\n" ); document.write( "\n" ); document.write( "Use the $\"Product\"$ $\"+Property\"$ .\r
\n" ); document.write( "\n" ); document.write( "= $\"log+4+%2B+log+6\"$ \r
\n" ); document.write( "\n" ); document.write( "Step 3\r
\n" ); document.write( "\n" ); document.write( "Substitute $\"0.602\"$ for $\"log+4\"$ and $\"0.778\"$ for $\"log+6\"$ .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "= $\"0.602+%2B+0.778\"$ \r
\n" ); document.write( "\n" ); document.write( "= $\"+1.38\"$ \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "so, $\"log+%2824%29=+1.38\"$
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