document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404116>Question 404116</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a set of data with a mean of 150 and a standard deviation of 25. Using Chebyshev's Theorem, what is the minimum percentage of data between 75 and 225? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285634 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 75 = 150 - 3*25 = 75, and 225 = 150 + 3*25 .  \r<BR>\n" );
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document.write( "Hence k = 3 in Chebyshev's theorem (or, within 3 sd's from the mean, plus-minus).\r<BR>\n" );
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document.write( "==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=P%28abs+%28X+-+mu%29+%3C=+3sigma%29+%3E=+1+-+1%2F3%5E2+=+8%2F9 ALIGN=MIDDLE  ALT=\"P%28abs+%28X+-+mu%29+%3C=+3sigma%29+%3E=+1+-+1%2F3%5E2+=+8%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >.\r<BR>\n" );
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document.write( "That is AT LEAST <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=88%268%2F9 ALIGN=MIDDLE  ALT=\"88%268%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" >% of the distribution between 75 and 225. </SPAN>\n" );
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