document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=404097>Question 404097</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do I justify each step in the equation:\r<BR>\n" );
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document.write( "5(n + 4) + 9n = (5n + 20 = 9n<BR>\n" );
document.write( "              = 5n + (20 + 9n)<BR>\n" );
document.write( "              = 5n + (9n + 20)<BR>\n" );
document.write( "              = (5n + 9n) + 20<BR>\n" );
document.write( "              = (5 + 9)n + 20<BR>\n" );
document.write( "              = 14n + 2o </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285614 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285614\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just use all the distributive, commutative laws out there:\r<BR>\n" );
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document.write( "5(n + 4) + 9n = (5n + 20) + 9n (distribute property)<BR>\n" );
document.write( "              = 5n + (20 + 9n) (associative property)<BR>\n" );
document.write( "              = 5n + (9n + 20) (commutative property)<BR>\n" );
document.write( "              = (5n + 9n) + 20 (associative property)<BR>\n" );
document.write( "              = (5 + 9)n + 20 (factoring out n)<BR>\n" );
document.write( "              = 14n + 20 (5 + 9 = 14) </SPAN>\n" );
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