document.write( "Question 403934: Given y is two times x, z is three times x, and x + y + 3z = 12. What are the values of x, y, and z ? \n" ); document.write( "
Algebra.Com's Answer #285528 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Given y is two times x, z is three times x, and x + y + 3z = 12. What are the values of x, y, and z ? \n" ); document.write( "---- \n" ); document.write( "Equations: \n" ); document.write( "y = 2x \n" ); document.write( "z = 3x \n" ); document.write( "x + y + 3z = 12 \n" ); document.write( "---- \n" ); document.write( "Substitutue and solve for \"x\": \n" ); document.write( "x + 2x + 9x = 12 \n" ); document.write( "12x = 12 \n" ); document.write( "x = 1 \n" ); document.write( "--- \n" ); document.write( "y = 2x = 2 \n" ); document.write( "z = 3x = 3 \n" ); document.write( "============================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "============= \n" ); document.write( " |