document.write( "Question 43553This question is from textbook College Algebra
\n" ); document.write( ": 4) John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r
\n" ); document.write( "\n" ); document.write( " Show clearly the algebraic steps which prove your dimensions are the maximum area which can be obtained.\r
\n" ); document.write( "\n" ); document.write( "Answer: \r
\n" ); document.write( "\n" ); document.write( "Show work in this space. \r
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Algebra.Com's Answer #28552 by stanbon(75887)\"\" \"About 
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John has 300 feet of lumber to frame a rectangular patio (the perimeter of a rectangle is 2 times length plus 2 times width). He wants to maximize the area of his patio (area of a rectangle is length times width). What should the dimensions of the patio be, and show how the maximum area of the patio is calculated from the algebraic equation.\r
\n" ); document.write( "\n" ); document.write( "Perimeter =2l+2w=300 ft.
\n" ); document.write( "Dividing by 2 you get:
\n" ); document.write( "l+w=150
\n" ); document.write( "Area=(length)(width)
\n" ); document.write( "Let length be \"l\"
\n" ); document.write( "Then width = \"150-l\"
\n" ); document.write( "Area=(l)(150-l)
\n" ); document.write( "Area=150l-l^2
\n" ); document.write( "This is a quadratic equation where a=-1 and b=150.
\n" ); document.write( "The maximum area is where l=-b/2a=-150/(-2)=75
\n" ); document.write( "So the maximum area is as follows:
\n" ); document.write( "Area=lw=(75)(150-75)=75(75)=5625 sq. ft.\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.\r
\n" ); document.write( "\n" ); document.write( "-b/2a=\r
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