document.write( "Question 403901: A 240in. Pipe is cut into two pieces. One piece is three times the length of the other. Find the lengths of the pieces. \n" ); document.write( "
Algebra.Com's Answer #285517 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "let one piece be \"x\" and another one \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"240in+=x%2By\"\r
\n" ); document.write( "\n" ); document.write( "since one piece is three times the length of the other, we have\r
\n" ); document.write( "\n" ); document.write( "\"x=3y\"..substitute in \"240in=x%2By\" and find \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"240in=3y%2By\"\r
\n" ); document.write( "\n" ); document.write( "\"240in=4y\"\r
\n" ); document.write( "\n" ); document.write( "\"240in%2F4=y\"\r
\n" ); document.write( "\n" ); document.write( "\"60in=y\"\r
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\n" ); document.write( "\n" ); document.write( "now find \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3%2A60in\"\r
\n" ); document.write( "\n" ); document.write( "\"x=180in\"\r
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\n" ); document.write( "\n" ); document.write( "the lengths of the pieces: 60in and 180in\r
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