document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403881>Question 403881</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a rectangle is 35. If the length is 2 more than the width, find the dimensions of the rectangle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285506 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285506\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> L=w+2\r<BR>\n" );
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document.write( "Area = Lw<BR>\n" );
document.write( "35 = (w+2)w<BR>\n" );
document.write( "35 = w^2 +2w<BR>\n" );
document.write( "0 = w^2 + 2w -35\r<BR>\n" );
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document.write( "Factor (or use the quadratic formula):\r<BR>\n" );
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document.write( "0=(w+7)(w-5)\r<BR>\n" );
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document.write( "w=-7, w=5\r<BR>\n" );
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document.write( "The width can't be a negative number, so we can't choose w=-7. The width must be 5.\r<BR>\n" );
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document.write( "We know that the length is 2 more than the width, so the length must be 7.\r<BR>\n" );
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document.write( "Dimensions:<BR>\n" );
document.write( "L=7<BR>\n" );
document.write( "w=5\r<BR>\n" );
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document.write( "Area = 7x5=35 </SPAN>\n" );
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