document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=403876>Question 403876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance from King Street to Prince Street is 21 km. It takes 30 minutes.<BR>\n" );
document.write( "What is the average speed of the bus between these two places? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #285504 by </B><A HREF=/tutors/aboutme.mpl?userid=texttutoring><B>texttutoring(324)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=texttutoring><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=texttutoring><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=285504\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The relationship between Distance, Speed and Time is found in this formula:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "D=ST\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "You have D at T, and you're looking for S. First, let's change T from 30 minutes to 0.5 hours, so that our speeed will be in km/h.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "D=ST<BR>\n" );
document.write( "21 = S(0.5)<BR>\n" );
document.write( "S = 21/0.5<BR>\n" );
document.write( "S = 42 km/h\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "So the average speed is 42 km/h.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps!<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );