document.write( "Question 403723: a sparrow flies to see a friend at a speed of 4km/h. his friend is out,so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how many far away does his friend Live? \n" ); document.write( "
Algebra.Com's Answer #285451 by mananth(16946)\"\" \"About 
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\n" ); document.write( "let distance be x km
\n" ); document.write( "while going to meet 4km/h
\n" ); document.write( "time taken = x/4
\n" ); document.write( "...
\n" ); document.write( "return speed = 5km/h
\n" ); document.write( "time = x/5
\n" ); document.write( "...
\n" ); document.write( "x/5 +x/4 = 54/60
\n" ); document.write( "(4x+5x)/20=54/60
\n" ); document.write( "9x=54*20/60
\n" ); document.write( "9x=18
\n" ); document.write( "/9
\n" ); document.write( "x= 2km====> distance friend lives
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