document.write( "Question 403723: a sparrow flies to see a friend at a speed of 4km/h. his friend is out,so the sparrow immediately returns home at a speed of 5km/h. the complete journey took 54 minutes. how many far away does his friend Live? \n" ); document.write( "
Algebra.Com's Answer #285451 by mananth(16946)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "let distance be x km \n" ); document.write( "while going to meet 4km/h \n" ); document.write( "time taken = x/4 \n" ); document.write( "... \n" ); document.write( "return speed = 5km/h \n" ); document.write( "time = x/5 \n" ); document.write( "... \n" ); document.write( "x/5 +x/4 = 54/60 \n" ); document.write( "(4x+5x)/20=54/60 \n" ); document.write( "9x=54*20/60 \n" ); document.write( "9x=18 \n" ); document.write( "/9 \n" ); document.write( "x= 2km====> distance friend lives \n" ); document.write( " \n" ); document.write( " |