document.write( "Question 5494: Solution A is 8% acid and Solution B is 4% acid. If a technician wants to mix them to make 150 liters of Solution C which is 6% acid, how many liters of each should be mixed together?
\n" );
document.write( " thanks for the help! \n" );
document.write( "
Algebra.Com's Answer #2854 by Abbey(339)![]() ![]() ![]() You can put this solution on YOUR website! Let A=volume (quantity) of 8% acid \n" ); document.write( "Let B=volume of 4% solution \n" ); document.write( "Amount of acid in the 8% solution is 8% of the volume, or .08A \n" ); document.write( "Amount of acid in the 4% solution is 4% of the volume, or .04B\r \n" ); document.write( "\n" ); document.write( "So if we want a total of 150 gallons we can say: \n" ); document.write( "the volume of A + the volume of B = 150 gallons, or \n" ); document.write( "A+B=150 \n" ); document.write( "this can be rewritten as A=150-B\r \n" ); document.write( "\n" ); document.write( "and the amount of acid we want is .06(150) (6% of the 150 gallons should be acid)\r \n" ); document.write( "\n" ); document.write( "so we can create an equation that states: \n" ); document.write( ",08A+.04B=.06(150)\r \n" ); document.write( "\n" ); document.write( "and since we know that A=150-B, we can substitute this into our equation: \n" ); document.write( ",08A+.04B=.06(150) \n" ); document.write( ",08(150-B)+.04B=.06(150) \n" ); document.write( "Then just solve for B: \n" ); document.write( "12-.08B+.04B=9 \n" ); document.write( "12-.04B=9 \n" ); document.write( "12=9+.04B \n" ); document.write( "3=.04B \n" ); document.write( "75=B\r \n" ); document.write( "\n" ); document.write( "We need 75 gallons of solution B, so we need 75 gallons of solution A\r \n" ); document.write( "\n" ); document.write( "put these answers into your equations to verify: \n" ); document.write( ",08(75)+.04(75)=.06(150) \n" ); document.write( "This is a true statement, so the answer is correct.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |