document.write( "Question 403636: A train leaves the station heading north at 125 mph, a second train leaves 2 hours later on a parallel track heading north at 175 mph how far from the station will they meet? \n" ); document.write( "
Algebra.Com's Answer #285370 by robertb(5830)\"\" \"About 
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Let d = the distance from the station to the catch-up point. Then from the formula t = d/r,
\n" ); document.write( "\"d%2F125+-+d%2F175+=+2\" <==> \"%282d%29%2F875+=+2\" \"d%2F875+=+1\", or d = 875 miles.
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\n" ); document.write( "\n" ); document.write( "There is yet another way of approaching this problem, and that is to let
\n" ); document.write( "t = time of travel of train 1 before the catch-up, and
\n" ); document.write( "t - 2 = time of travel of train 2 before the catch,
\n" ); document.write( "and then use the formula d = rt, to get the equation 125t = 175(t-2).
\n" ); document.write( "But this is indirect...
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