document.write( "Question 158128This question is from textbook Algebra and trigonometry
\n" ); document.write( ": A woman driving a car 14 ft long is passing a truck 30 ft long. The truck is traveling at 50 mi/h. How fast must the woman drive her car so that she can pass the truck completely in 6 s, from the position shown in figure (A) to the position shown in figure (B)?
\n" ); document.write( "(A)\r
\n" ); document.write( "\n" ); document.write( "---CARI --->
\n" ); document.write( "---------I
\n" ); document.write( "---------IT-R-U-C-K -->
\n" ); document.write( "---------I\r
\n" ); document.write( "\n" ); document.write( "(B)
\n" ); document.write( "-------------I
\n" ); document.write( "-------------ICAR -->
\n" ); document.write( "-------------I
\n" ); document.write( " T-R-U-C-KI --->
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Algebra.Com's Answer #285344 by cattycassie77(2)\"\" \"About 
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264,000 per hour
\n" ); document.write( "264000ft/3600 sec
\n" ); document.write( "(264,000/3600)=(x/6)
\n" ); document.write( "x=440 feet+16+30=484 ft/6sec
\n" ); document.write( "290400ft/3600 sec
\n" ); document.write( "55 miles per hour
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